Which of the following is the correct order?

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(D) $1$. The extent of $H$-bonding depends on the number of $H$-bonds per molecule. $HF$ has $2$ $H$-bonds,$H_2O$ has $4$ $H$-bonds,and $H_2O_2$ has $

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All of these

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(D) $1$. The extent of $H$-bonding depends on the number of $H$-bonds per molecule. $HF$ has $2$ $H$-bonds,$H_2O$ has $4$ $H$-bonds,and $H_2O_2$ has $6$ $H$-bonds. Thus,the order of extent is $HF $2$. The strength of an $H$-bond depends on the electronegativity of the atom bonded to $H$. $F$ is more electronegative than $O$,so the $H$-bond strength order is $HF > H_2O > H_2O_2$.$3$. Due to the open cage-like structure of ice $(H_2O(s))$ formed by $H$-bonding,its density is lower than that of liquid water $(H_2O(\ell))$. Thus,$H_2O(\ell) > H_2O(s)$ is correct.$4$. Since all statements are correct,the answer is $D$.

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